| Applications of Exponential Functions |
-- Section 4.2 -- |
| Radioactive Decay (Half-life): |
A = Ao2-t/h where A = Amount, Ao is initial amount when t = 0 and h is half-life |
| The
half-life of radioactive radium Ra226 is 1,620 years. How much of a 100 gram sample will remain after 500 years? |
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Solve |
Step |
Calculator Help |
| Find A using A = Ao2-t/h | Half-life formula | Most calculators....use ^ or xy for exponent key |
Identify
each part |
HINT: use these key strokes | |
Ao=
100 |
initial amount | 500 × 2 ^ (-500÷1620) [enter or =] |
t =
500 |
time in years | |
h =
1620 |
half-life in years | |
| A = 500(2)-500/1620 » 403.7 | Half-life | Half-life means there is half the original (initial) amount left after t years. |
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| The
half-life of radioactive plutonium Pu226 is 24,360 years.
How much of a 4,000 gram sample will remain after 30,000 years? |
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[Solution] |
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| The population of a country increases according
to the model: P = 200e0.03t where t is time in years with t = 0 corresponding to 1995. Find the population in 2010. (population given in millions: 200 represent 200,000,000) |
| Population Growth : | P = Poekt where P = population, Po is initial population when t = 0 and k is annual growth rate |
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Solve |
Step |
Calculator Help |
| Find P using P = Poekt | Growth formula | Most calculators....use ^ or xy for exponent key |
Identify
each part
|
HINT: use these key strokes | |
Po=
200
|
initial amount in millions | 200×e ^ (0.03×15) [enter or =] |
t =
15
|
time in years 2010 - 1995 = 15 | Recall e » 2.718281828459045.... |
k =
0.03
|
growth constant - given k = 0.03 | |
| P = 200e0.03(15) » 313.7 | Growth formula | You will find k in using logarithms in latter sections. |
| Interpret Þ There would be about 313.7 million people in the year 2010. | ||
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The population of a country increases
according to the model: |
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[Solution] |
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| The concentration
x of a certain drug in an organ after t minutes is
given by x = 0.07(1 - e-0.1t ). Find the concentration of the drug at 1 hour. |
|
Solve |
Step |
Calculator Help |
| Find x using x = 0.07(1 - e-0.1t ) | Given concentration formula | Most calculators....use ^ or xy for exponent key |
Identify
each part
|
HINT: use these key strokes | |
t =
60
|
Since 60 minutes = 1 hour | 0.07×(1 - e ^ (-0.1×60)) [enter or =] |
| x = 0.07(1 - e-0.1(60) ) » 0.0698 | Growth formula | You need both sets of parentheses. |
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The concentration x of
a certain drug in an organ after t minutes is given by |
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[Solution] |
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Tutorials and Applets by
Joe McDonald
Community College of Southern Nevada