| Operations on functions |
-- Section 3.6 -- |
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Composite Functions |
(f og)(x) = f(g(x))
The circle means composite. |
| Let f(x) = 2x - 1 and g(x) = 5x. Find (f og)(x)and (g o f)(x) |
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Solve |
Step |
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(f og)(x) = f(g(x)) = f(5x) |
Substitute g(x) into f(x) | |
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= 2(5x) - 1 = 10x - 1 |
We have a new function 10x - 1 | |
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(g of)(x) = g(f(x)) = g(2x - 1) |
Substitute f(x) into g(x) | |
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= 5(2x - 1) = 10x - 5 |
We have a new function 10x - 5 | |
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Notice that 10x
- 1 ¹
10x - 5
(f og)(x)
and (g o f)(x)
may not be equal |
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| Let f(x) = 3x + 2 and g(x) = 2x - 4. Find (f og)(x) and (g o f)(x) |
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[Solution] |
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| Let f(x) = 4x2 + 1 and g(x) = x - 1. Find (f og)(x) and (g o f)(x) |
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Solve |
Step |
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(f og)(x) = f(g(x)) = f(x - 1) |
Substitute g(x) into f(x) | |
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= 4(x - 1)2 + 1 |
Don't forget the "+ 1" | |
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= 4(x2 - 2x + 1) + 1 |
(x - 1)2 = (x - 1)(x - 1) = x2 - x - x + 1 = x2 - 2x + 1 | |
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= 4x2 - 8x + 4 + 1 |
We have a new function 10x - 1 | |
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= 4x2 - 8x + 5 |
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(g of)(x) = g(f(x)) = g(4x2 + 1) |
Substitute f(x) into g(x) | |
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= (4x2 + 1) - 1 = 4x2 |
Simplify | |
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= 4x2 |
We have a new function 4x2 | |
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Notice that 4x2
- 8x + 5
¹ 4x2
(f og)(x)
and (g o f)(x)
may not be equal |
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Let f(x) = 2x2 + 3 and g(x) = x - 3. Find (f o g)(x) and (g o f)(x) |
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[Solution] |
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| Let f(x) = 4x2 + 1 and g(x) = x - 1. Find (f o g)(2) and (g o f)(-5) |
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Solve |
Step |
Check |
| Another way | First find |
From Example 2 |
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Find (f o g)(2) = f(g(2)) = ? |
First find g(2) |
(f og)(x) = 4x2 - 8x + 5 |
| g(2) = 2 - 1 = 1 |
Substitute 1
into f(x) |
(f ° g)(2) = 4(2)2 - 8(2) + 5 |
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f(1) = 4(1)2 + 1 = 4(1) + 1 = 5 |
(f ° g)(1) = 5 |
(f ° g)(2) = 16 -
16 + 5 = 5 |
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Find (g of)(-5) = g(-5) = ? |
First find f(-5) |
(g of)(x) = 4x2 |
| f(-5) = 4(-5)2 + 1 = 4(25) + 1 = 101 |
Substitute 101
into g(x) |
(g of)(-5)
= 4(-5)2 = 2(25) =100 |
| g(101) = 101 - 1 = 100 | ||
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Let f(x) = 2x2 + 3 and g(x) = x - 3. Find (f o g)(3) and (g o f)(-4) |
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[Solution] |
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Tutorials and Applets by
Joe McDonald
Community College of Southern Nevada